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sattari [20]
3 years ago
5

What ate the two safety precautions that should be taken before driving your car?

Physics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

When traveling behind other vehicles, there should be at least a four second space between your vehicles. When the car in front of you passes a stationary object, slowly count to yourself. If you pass the object before the allotted time, you should back off. When traveling at night or inclement weather, these times should be doubled.

Don't talk on a cell phone while driving. Phones detract from your ability to concentrate on the road and increase your chance of a collision by nearly 400%. If you must use the phone, pull over to a safe, well-lit parking lot and place your call there. After completing your call you may continue on your way.bey all speed limits and signs.

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A 23-newton horizontal force westward and a 23-newton horizontal force eastward act concurrently on a 10-kilogram object on a fr
BARSIC [14]
The forces cancel out each other because they are equal and opposite. Therefore the net force is 0 and there will be no acceleration

7 0
3 years ago
The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the
Andru [333]
<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"

So, option B is your answer

Hope this helps!
</span>
5 0
4 years ago
Would you be doing more work going up the stairs twice as fast?
SSSSS [86.1K]
If you use the stairs at normal speed, you will survive longer, and go up higher.
When going up the stairs twice as fast, you lose energy more quickly, but height would remain the same.
7 0
3 years ago
Read 2 more answers
Wave 1 displaces according the function f(θ)= 2sin θ+1. Wave 2 displaces according to the function f(θ)= 3sin θ+.5. At what angl
r-ruslan [8.4K]

Answer:

θ = 30⁰  

Explanation:

We have been given two wave displacement equations,

y_{1} =2sin\theta +1     ........(1)

y_{2}=3sin\theta +0.5     ........(2)

The waves will have same displacements when y_{1}=y_{2}=y (say)

Therefore, operating (2) - (1), we get,

sin\theta - 0.5=0

or, \theta = sin^{-1}(0.5)=30^{o} (since, sin 30⁰ = 0.5)

We can check the answer by putting \theta=30^{o} in equations (1) and (2),

y_{1}=2sin30^{o}+1=2\times0.5 + 1= 2

y_{2}=3sin30^{o}+0.5=3\times0.5+0.5=1.5+0.5=2

6 0
3 years ago
Read 2 more answers
Calculate the force between two objects that have masses of 70 kilograms and 2,000 kilograms separated by a distance of 1 meter.
Makovka662 [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Gravitational Force between given objects will be ~

  • 9.34 \times  {10}^{ - 6}  \:  \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where ~

  • F = gravitational force

  • m_1 = mass of 1st object = 70 kg

  • m_2 = mass of 2nd object = 2000 kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 1 m

Let's calculate the force ~

  • F =  \dfrac{6.674 \times 10 {}^{ - 11} \times 70 \times 2000 }{1 {}^{2} }

  • F =6.674 \times 7 \times 2 \times 10 { }^{ - 11} \times 10 {}^{4}

  • 93.436 \times 10 {}^{ - 7}

  • 9.3436  \times 10 {}^{ - 6} \:  \:  newtons
6 0
3 years ago
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