Answer:
12.7 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 56.7 Km/hr
Maximum height (h) =..?
First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:
Initial velocity (m/s) = 56.7 x 1000/3600
Initial velocity (m/s) = 15.75 m/s
Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:
Initial velocity (u) = 15.75 m/s
Final velocity (v) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
v = u – gt (since the ball is going against gravity)
0 = 15.75 – 9.8 × t
Rearrange
9.8 × t = 15.75
Divide both side by 9.8
t = 15.75/9.8
t = 1.61 secs.
Finally, we shall determine the maximum height as follow
h = ½gt²
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 1.61 secs.
Height (h) =..?
h = ½gt²
h = ½ × 9.8 × 1.61²
h = 4.9 x 1.61²
h = 12.7 m
Therefore, the maximum height reached by the ball is 12.7 m
Protons have a positive charge. Electrons have a negative charge. Neutrons have no (neutral) charge.
Answer:
B. is subject to a smaller net force but same acceleration.
Explanation:
F = m*a
So because our force applied is constant from the women pulling on the rope which means the acceleration is the same on both the 4kg create and the 6kg create. The only thing that changes here is the mass of the creates, so there is more tension force between the women and the 6kg create then there is between the 4kg create and the 6kg. It takes less force to move the 4kg create therefore the tension force is less between the two creates.
If it is average speed per hour, then you just have to divide 3.5 into 60
60/3.5 = 17.143 so around 17km/h
Answer:
3.8 x 10^10 m/s^2
Explanation:
Charge, q = 2 e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C
Electric field strength, E = 790 N/C
mass of helium nucleus, m = 6.645 x 10^-27 Kg
the force due to electric filed on a charge particle is given by
F = q x E
Where, q be the charge on the charged particle and E be the strength of electric field.
By substituting the values
F = 3.2 x 10^-19 x 790
F = 2528 x 10^-19 N
According to the Newton's second law
F = m x a
Where, me be the mass and a be the acceleration
By substituting the values
a = 3.8 x 10^10 m/s^2
