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4 years ago

Where is the location of a proton, and neutron?

Physics

2 answers:

Orlov [11]4 years ago

8 0

The Nucleus. In the center on an atom.

balandron [24]4 years ago

3 0

protrons and neutrons are found in the center of the atom.

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A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just

Sladkaya [172]

Answer:

option C and D

Explanation:

When a stunt driver is rotating on the banked road the force which is responsible for the centripetal acceleration of the car is Frictional force and the Normal Force.

The Frictional force component of the banked road will protect the car from skidding.

And the normal force component will protect the car from toppling inward due to centripetal force acting on it.

Hence, the correct answer is option C and D

7 0

3 years ago

A 958-N rocket is coming in for a vertical landing. It starts with a downward speed of 25 m/s and must reduce its speed to 0m/s

Art [367]

Answer:

T=1263.16N

Explanation:

A 958-N rocket is coming in for a vertical landing. It starts with a downward speed of 25 m/s and must reduce its speed to 0m/s in 8.0 seconds for the final landing. During this landing maneuver, what must be the thrust due to the rockets engines?

force is that which tends to cane a body state of rest or uniform motion in a straight line

it is also the pull or pus on an object.

the forces involved here to get the thrust on an object, are the weight and the force of gravity

W=mg

958=m*9.81

m=958/9.81

m=97.655kg

T=m(g+a)................................1

to get a

v=u+at

a=dv/dt

a=25/8

a=3.125m/s^2

acceleration is change in velocity per time

juxtaposing into the equation 1

T=97.655(9.81+3.125)

T=1263.16N

3 0

3 years ago

For a pendulum with period of oscillation, T, if the mass of the bob is reduced by half what will be the new period of oscillati

user100 [1]

Answer:

c. T

and the new period is $T'=4T$

Explanation:

the period of a pendulum is given by:

$T=2\pi \sqrt{\frac{l}{g} }$

as we can see the period of oscillation of the pendulum does not depend on the mass, so if the mass is reduced this will not affect the period, it will remain the same.

The new period if thr pedulum oscilates on Pluto, will be calculated with the previous equation, but the gravity will be

$g'=\frac{1}{16}g$

where g is the gravity on earth: $g=9.8m/s^2$

so the new period:

$T=2\pi\sqrt{\frac{l}{g'} } =2\pi\sqrt{\frac{l}{\frac{1}{16} g} } =2\pi\sqrt{\frac{16l}{ g} } =2\pi \sqrt{16}\sqrt{\frac{l}{ g} } =4(2\pi \sqrt{\frac{l}{ g} })$

and we know that

$(2\pi \sqrt{\frac{l}{ g} })$ is the original period $T$

so the new period in terms of the orginal period is:

$T'=4T$

3 0

3 years ago

Disturbances inside Earth’s core cause earthquakes. The starting point of the disturbance is called the epicenter. Why does the

Serhud [2]

The answer is; The waves encounter entirely different mediums

The amplitude is higher in highly elastic medium (rock) while the amplitude is lower is lessens elastic medium/rock. When the seismic waves meet a denser medium the amplitude decreases (and the frequency increases). This effect resembles the refraction of light waves. The energy of the wave dissipates as it spreads over a large and larger area from the epicenter.

4 0

4 years ago

Read 2 more answers

A fish is 17.9 cm from the front surface of a fish bowl of radius 45 cm. Where does the fish appear to be to someone in air view

AleksAgata [21]

Answer:

Fish will appear at distance 14.9 cm from the surface of bowl

Explanation:

As we know that fish is floating inside the water in fish bowl while it is observed from outside in air

so we have

$\frac{\mu_2}{d_i} - \frac{\mu_1}{d_o} = \frac{\mu_2 - \mu_1}{R}$