Answer:
r = 50[m]
Explanation:
Since the instrument has an operating or range radius, we must calculate this working distance or radius. We can determine the working area with the values that were given to us.
Now using the area of the circle we can find the radius.
Answer:
Explanation:
Given that
We know that from continuity equation
So
Now from energy equation
Q=6.17 x 0.08
Answer:1.9 meters
Explanation:
Wavelength=velocity ➗ frequency
Wavelength=18.81 ➗ 9.9
Wavelength=1.9
Wavelength is 1.9 meters
Answer:
a) -180.7 kN/C
b) -474.3 kN/C
c) 180.7 kN/C
Explanation:
For infinite planes the electric field is constant on each side, and has a value of:
E = σ / (2 * e0) (on each side of the plate the field points in a different direction, the fields point towards positive charges and away from negative charges)
The plate at -5 m produces a field of:
E1 = 2.6*10^-6 / (2 * 8.85*10^-12) = 146.8 kN/C into the plate
The plate at 3 m:
E2 = 5.8*10^-6 / (2 * 8.85*10^-12) = 327.5 kN/C away from the plate
At x < -5 m the point is at the left of both fields
The field would be E = 146.8 - 327.5 = -180.7 kN/C
At -5 m < x < 3 m, the point is between the plates
E = -146.8 - 327.5 = -474.3 kN/C
At x > 3 m, the point is at the right of both plates
E = -146.8 + 327.5 = 180.7 kN/C
In order to calculate the time taken by the snowball to reach the highest point in its journey, we need to consider the variables along the y-direction.
Let us list out what we know from the question so that we can decide on the equation to be used.
We know that Initial Y Velocity = 8.4 m/s
Acceleration in the Y direction = -9.8 m/, since the acceleration due to gravity points in the downward direction.
Final Y Velocity = 0 because at the highest point in its path, an object comes to rest momentarily before falling down.
Time taken t = ?
From the list above, it is easy to see that the equation that best suits our purpose here is
Plugging in the numbers, we get 0 = 8.4 - (9.8)t
Solving for t, we get t = 0.857 s
Therefore, the snowball takes 0.86 seconds to reach its highest point.