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3 years ago

What is the range of the function shown below f(x)=-12/x^2+6

Mathematics

2 answers:

GaryK [48]3 years ago

6 0

Answer:

Answer is d

Step-by-step explanation:

A P E X

Musya8 [376]3 years ago

4 0

Answer:

not sure i hope you find someone to help u tho soon

Step-by-step explanation:

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What is the value of x ? <br> A : 15<br> B : 30 <br> C: 45 <br> D : 60

jenyasd209 [6]

Answer:

Step-by-step explanation:

So that is a 90 degree angle and there is an angle of 30. 30-90 is 60. 60 divided by 4 is 15. So thus the answer is A,15.

7 0

3 years ago

Read 2 more answers

The Stock Market nadia is a stockbroker. Earns 14% commission each week. Last week, sold 7200$ worth of stocks. How much did

elena-s [515]

Answer:

Step-by-step explanation:

C=0.14×7,200=1008

Nadia made a total of $1008 last week in commission sales

b). To express the total amount she made in 2011, we derive the formula below;

Total amount (2011)=Average weekly commission× number of weeks in 2011

where;

Average weekly commission=$1008

number of weeks in 2011=52

replacing;

Total amount (2011)=(1008×52)=52,416

The total amount Nadia in commission in 2011=$52,416

4 0

3 years ago

H=7+44t-16^2

djyliett [7]

Answer:

$t_1\approx2.18$

$t_2\approx0.57$

Step-by-step explanation:

$h=7+44t-16t^2$

$27=7+44t-16t^2$

$0=-20+44t-16t^2$

$0=-16t^2+44t-20$

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$t=\frac{-44\pm\sqrt{44^2-4(-16)(-20)}}{2(-16)}$

$t=\frac{-44\pm\sqrt{1936-1280}}{-32}$

$t=\frac{-44\pm\sqrt{656}}{-32}$

$t=\frac{-44\pm4\sqrt{41}}{-32}$

$t=\frac{11}{8}\pm\frac{\sqrt{41}}{8}$

$t_1\approx2.18$

$t_2\approx0.57$

5 0

2 years ago

If you're good at trig please help meeeee

tino4ka555 [31]

Answer:

x ≈ 77°, y = 103°

Step-by-step explanation:

Using the Sine rule in Δ BCD

$\frac{2.9}{sin45}$ = $\frac{4}{sinx}$ ( cross- multiply )

2.9sinx° = 4sin45° ( divide both sides by 2.9 )

sinx° = $\frac{4sin45}{2.9}$ , thus

x = $sin^{-1}$ ( $\frac{4sin45}{2.9}$ ) ≈ 77° ( to the nearest degree )

Since AC and DC are congruent then Δ ACD is isosceles.

Thus the base angles are congruent, that is

∠ ADC = ∠ CAD = y°

x and y are adjacent angles and supplementary, thus

x + y = 180, that is

77 + y = 180 ( subtract 77 from both sides )

y = 103°

4 0

2 years ago

The length of a bridge on a map is 1.5 cm. What is the actual length of the bridge in meters if the map is drawn at a scale of 1

Vitek1552 [10]

Answer:

The actual length of the bridge is 600 meters

Step-by-step explanation:

we know that

The scale on a map is

$\frac{1}{40,000}$

That means

1 unit on a map represent 40,000 units in the actual

1 cm on a map represent 40,000 cm in the actual

Remember that

$1/ m=100/ cm$

$40,000\ cm=40,000/100=400\ m$

we can rewrite the scale as

$\frac{1}{400}\frac{cm}{m}$

using proportion

Find out the actual length of the bridge in meters if the length of a bridge on a map is 1.5 cm.

Let

x ----> the the actual length of the bridge in meters

$\frac{1}{400}\frac{cm}{m}=\frac{1.5}{x}\frac{cm}{m}\\\\x=400(1.5)\\\\x=600\ m$

6 0

3 years ago