How much heat is required to convert 2.55g of water at 28.0 degree celsius to steam 100 degree celsius

1 answer:

4 0

767.448 Joules of heat is required.
You use the equation Q=MCdeltaT
Make sure you convery celsius to Kelvin
Specific heat of water is 4.18
So it will be Q=2.55(4.18)(72)
Q=767.448

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