Answer:
The answer is
<h2>15.86 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
![volume = \frac{mass}{density} \\](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7Bmass%7D%7Bdensity%7D%20%5C%5C)
From the question
mass of glycerol = 20 g
density = 1.261 g/mL
The volume is
![volume = \frac{20}{1.261} \\ = 15.86042823...](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B20%7D%7B1.261%7D%20%20%20%5C%5C%20%20%3D%2015.86042823...)
We have the final answer as
15.86 mL
Hope this helps you
IDK JUST NEED ANSWERS,BTW IM DUMB
Answer:
The symbol that represent a salt is CaCl2
Explanation:
The CaCI2 is the calcium chloride that an organic compound now a salt having a chemical formula i.e. CaCI2. Also it is non-color cyrstalline solid at the room temperature also it is highly soluble in the water
Therefore as per the given situation the symbol that represent a salt is CaCI2
This is the answer and the same is not provided in the given options
Answer:
After the reaction, there will 0.60 g of magnesium oxide and 0.25 g of oxygen gas present in the tube
Explanation:
Equation of the reaction between magnesium and oxygen is given as follows:
2Mg(s) + O₂(g) ---> 2MgO(s)
From the equation of reaction, 2 moles of magnesium reacts with i mole of oxygen gas to produce 1 mole of magnesium oxide
molar mass of magnesium is 24.0 g; molar mass of oxygen gas = 32.0 g; molar mass of magnesium oxide = 40.0 g
Therefore 24 g of magnesium reacts with 32 g of oxygen gas
I.00 g of magnesium will react with (24.0 / 32.0) * 1.00 g of oxygen = 0.75 g of oxygen gas.
Therefore, magnesium is the limiting reagent. Once it is used up, the reaction will stop and the excess oxygen will be left in the tube together with the product, magnesium oxide.
mass of excess oxygen = 1.00 - 0.75 = 0.25 g
mass of magnesium oxide formed = (24.0 / 40.0 g) * 1 = 0.60 g