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2 years ago

14

Carmen eats 1/3 of his granola bar before before school and another 1/3 of the granola bar for lunch. Draw and shade a fraction

bar to show how much of the granola bar Cameron has eaten.

1 answer:

emmasim [6.3K]2 years ago

7 0

So he’s eaten 2/3 already
make a rectangle with three sections
shade in two of the sections
and that shows how much of the granola bar he’s eaten

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Tatiana [17]

Answer: 103/15

Step-by-step explanation:

We can simplify the right-hand side to be $2 \left(\frac{1}{3}+6 \right)=2 \left(\frac{19}{3} \right)=\frac{38}{3}$ .

This means we need to solve:

$\frac{1}{2}(5x-9)=\frac{38}{3}\\5x-9=\frac{76}{3}\\5x=\frac{103}{3}\\x=\boxed{\frac{103}{15}}$

7 0

1 year ago

Write the number 4<br> 4 as a product of prime factors.

Paladinen [302]

The answer would be
2 x 2 = 4

7 0

3 years ago

What is 33 and 1/3 as a percent?

GarryVolchara [31]

Answer:

33 is 33 % of 100 and 1/3 is 33.33 %

Step-by-step explanation:

Hope this helps!!

6 0

3 years ago

Read 2 more answers

-7+b=-8 step by step plz

Gelneren [198K]

Answer:

b=-1

Step-by-step explanation:

-7+b=-8

Add 7 to each side to isolate b

-7+7+b=-8+7

b = -1

7 0

2 years ago

Read 2 more answers

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0

2 years ago