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3 years ago

Which choice is NOT a way to find 9 ÷ 4?

1 answer:

5 0

D is wrong. D= 0.4 (roughly) A B and C are the same thing = 2.25 9 divided by 4=2.25 In math OF means TIMES (like multipling) and a fraction is dividing :) Hope this helps

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Help me answer this question please

Stella [2.4K]

ANSWER

${f}^{ - 1} =\pm \sqrt{x + 1}$

EXPLANATION

The given function is

$f(x) = {x}^{2} - 1$

Let

$y = {x}^{2} - 1$

Interchange x and y to get:

$x= {y}^{2} - 1$

Solve for y,

$x + 1 = {y}^{2}$

Take square root of both sides to get,

$\pm \sqrt{x + 1} = y$

This is the same as:

$y = \pm \sqrt{x + 1}$

Therefore the inverse is

${f}^{ - 1} =\pm \sqrt{x + 1}$

3 0

3 years ago

A senior paid $3.47, $9.50 and $2.50 for lunch during a basketball tournament. What was the average amount he paid over three da

cestrela7 [59]

Answer:

The average amount he paid over 3 days is $15.47.

Step-by-step explanation:

4 0

2 years ago

What’s the slope intercept form of (2,5) and (0,1)

Travka [436]

Answer:

y=2x+1

Step-by-step explanation:

First you have to find the slope:

5-1/2 so 4/2 or 2

Then you write it in point-slope: (I used the point (0,1))

y-1=2x

Simplify than:

y=2x+1

8 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$