We have a "rectangular" double loop, meaning that both loops go to completion.
So there are 3*4=12 executions of t:=t+ij.
Assuming two operatiions per execution of the innermost loop, (i.e. ignoring the implied additions in increment of subscripts), we have 12*2=24 operations in all.
Here the number of operations (+ or *) is exactly known (=24).
Big-O estimates are used for cases with a varying scale of operations, governed by a variable (usually n) to indicate the sensitivity of the number of operations relative to a change in the size of n.
Here we do not have a scale, nor n is defined. The number of operations is constant and known at 24. So a variable is required to find the big-O estimate.
Using the surface area formula for rectangular and triangular prism, the surface area of the composite figure is: 444 m².
<h3>What is the Surface Area of the Composite Figure?</h3>
Total surface area = surface area of the top triangular prism + surface area of the bottom rectangular prism - area of the surface both share together.
Surface area of the top triangular prism = (S1 + S2+ S3)L + bh = (10 + 10 + 16)5 + (16)(6) = 276 m².
Surface area of the bottom rectangular prism = 2(wl + hl + hw) = 2·(5·16+4·16+4·5) = 328 m²
Area of the surface both share together = 2(16)(5) = 160 m²
Total surface area = 276 + 328 - 160 = 444 m².
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Any number that makes an equation true is a "solution of an equation" it id a solution....(i hope this helps) *smiles*
2.5
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Answer:
x=11, y=8/3
Step-by-step explanation:
Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then
LM=NO
and
LO=MN
Thus,
Solve this system of two equations. From the first equation:
Substitute it into the second equation:
