Answer:
Confidence interval = ( 0.7991, 0.8647 )
Step-by-step explanation:
Sample size = n = 351
number of successes = X = 292
Sample proportion = P = 
= 
= 0.831908831
confidence interval = 90%
Critical Z value = 1.6449 [by using excel]
Confidence interval = P ± Z 
Where P = Sample proportion
Z = critical value
n = sample size
Confidence interval = 0.831908831 ± 1.6449 
= 0.831908831 ± 1.6449 × 0.0200
= 0.831908831 ± 0.032898
Lower limit = 0.831908831 - 0.032898 = 0.7991
Upper limit = 0.831908831 + 0.032898 = 0.8647
Confidence interval = ( 0.7991, 0.8647 )
4-2(1)=
4-2=2
So basically the answer is 2
Answer:
10 ball caps
Step-by-step explanation:
In this question, we are trying to know the number of caps the manger would buy that would equate the cost at both companies.
How do we get this?
Since we do not know the number of caps, let’s assign a variable. Let the number of caps that is required be x. Let’s now make some costings in terms of x. We proceed;
Company X charges $50 fee plus $7 per cap. Total amount company X will charge on x caps will be; $50 + $7(x) = $50 + $7x
Company Y will charge $30 plus $9 per cap. Total amount company Y will charge on x caps will be $30 + $9(x) = $30 + $9x
We are trying to look at the value of x that will make both costs equal. What we do is to equate both costs.
30 + 9x = 50 + 7x
We simply by taking like terms to the same sides
9x-7x = 50-30
2x = 20
x = 20/2 = 10
X = 10
So what this means is that manger has to buy 10 caps to have the same cost in both companies
Yeah sure, but i need to see the picture to get your answer
