7\10 cause 5 and 10 can both go into 10 and 5 goes into ten twice so multiply the top number by 2 and 3\10 stays the same because 10 goes into 10 one time.
Answer:
644
Step-by-step explanation:
Is there more to this? I don’t quite understand
Answer:
Commutative property of addition of rational numbers: Two rational numbers can be added in any order. Thus for any two rational numbers a/b and c/d, we have. (a/b + c/d) = (c/d + a/b)
B is the best answer for this problem.
Sorry if I’m wrong