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3 years ago

the length of a chord of a circle is 24 cm long and is 5 cm away from the center of the circle what is the radius of the circle

2 answers:

iogann1982 [59]3 years ago

4 0

Answer:A chord with length 24 cm at 5 cm from the center gives a radius of 13 cm, using a half-length of 12 cm and the distance of 5 cm in Pythagoras’s theorem to find the radius.

Using the same radius and Pythagoras's theorem again, a chord 10 cm from the circle with radius 13 cm has a half-length of sqrt(69), or a full length of double that, so 2*sqrt(69).

can i have brainlest

Elodia [21]3 years ago

3 0

Answer:

Step-by-step explanation:

radius of the circle (r) = √12²+5² = √169 = 13

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Students were packed shoulder to shoulder in a gym for a pep rally. The students were in a rectangular shaped area of 7,500 ft2.

hram777 [196]

Answer: 1527

Step-by-step explanation:

Total Area = 7500 ft^2

Area covered by one student = Area of one circle

= π*r^2

r = radius of circle = 2.5/2 = 1.25 ft

Area covered by one student = π*1.25^2 = 4.91 ft^2

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3 years ago

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lukranit [14]

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Step-by-step explanation:

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2 years ago

Find the length of a diagonal<br> of a square with sides of 14<br> feet long.<br> [?][feet<br> /

inessss [21]

Answer:

14√2 feet

Step-by-step explanation:

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3 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$

Because if we find the parameters we got:

$E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu$

$Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}$

And the deviation would be:

$Sd (\bar X) = \frac{\sigma}{\sqrt{n}}$

And we satisfy the condition:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

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3 years ago

The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is

pickupchik [31]

range is all the y values.
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3 years ago

the length of a chord of a circle is 24 cm long and is 5 cm away from the center of the circle what is the radius of the circle​

the length of a chord of a circle is 24 cm long and is 5 cm away from the center of the circle what is the radius of the circle