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3 years ago

HOW DO YOU CONVERT SURFACE AREA TO VOLUME! HELP!!!! WILL MARK BRAINLIST!!

Mathematics

1 answer:

slamgirl [31]3 years ago

3 0

Answer:

Formulas for a rectangular prism:

Volume of Rectangular Prism: V = lwh.

Surface Area of Rectangular Prism: S = 2(lw + lh + wh)

Space Diagonal of Rectangular Prism: (similar to the distance between 2 points) d = √(l2 + w2 + h2)

Step-by-step explanation:

Hope it helps :))))

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Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)

Lorico [155]

Answer:

It is proved that $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$ .

Step-by-step explanation:

We already have the identity of x as $\sin ^{2}x + \cos ^{2}x = 1$ .......... (1) .

So, from equation (1) we can write that

$\cos ^{2} x = 1 - \sin ^{2} x$

⇒ $6\cos ^{2} x = 6 - 6 \sin ^{2} x$

⇒ $6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3$

⇒ $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$

Hence, it is proved that $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$ . (Answer)

5 0

3 years ago

A. How many centimeters across a handprint

vladimir2022 [97]

Answer:7.87402

Step-by-step explanation: please leave a thx! :)

3 0

3 years ago

Read 2 more answers

A train leaves at 17.22 and arrives at its destination at 18.14.

sattari [20]

Answer:

64.6 km/h

Step-by-step explanation:

18:14 = 18h 14'

1h = 60'

18h = 17h + 60'

18h14' = 17h + 60' ´14' = 17h 74'

then:

17h 74'

-17h 22'

= 0h 52'

the train travelled 56km at 52 minutes

56km/52minutes

1 hour = 60 minutes

52 minutes = 52/60 = 0.86667 hours

then:

56km/52minutes = 56km/0.86667hours

= 64.615 km/hours

5 0

2 years ago

Maggie is standing on a platform that is 8 feet above the ground. She throws a ball in the air that hits the ground after 2 seco

Paha777 [63]

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

<h3>How to find the free fall formula for a given scenario</h3>

An object experiments a free fall when it is solely accelerated by gravity on the assumption of an <em>uniform</em> acceleration. The formula is described below:

$h =h_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2}$ (1)

Where:

$h_{o}$ - Initial height, in feet.
$v_{o}$ - Initial speed, in feet per second.
$t$ - Time, in seconds.
$g$ - Gravitational acceleration, in feet per square second.

If we know that $t = 2\,s$ , $h_{o} = 8\,ft$ , $h = 0\,ft$ , $g = -32.174\,\frac{ft}{s^{2}}$ , then the height formula is:

$0 = 8 +2\cdot v_{o} - \frac{1}{2}\cdot (32.174)\cdot (2)^{2}$

$0 = -56.348+2\cdot v_{o}$

$v_{o} = 28.174\,\frac{ft}{s}$

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105

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3 years ago

3x^2+ 4x + 5 for x = -2

Alexus [3.1K]

The answer is 33
3(-2)^2+4(-2)+5
-6^2+ (-8) + 5
36 + (-8) + 5
28+5
33

7 0

3 years ago