Question

Given the system of constraints name all vertices. Then find the maximum value of the given objective

Answer 1

Answer:

$35$

Step-by-step explanation:

The constraints are

The red line represents the function

$y\leq \dfrac{1}{3}x+1$

At $y=0$

$0=\dfrac{1}{3}x+1\\\Rightarrow -1=\dfrac{1}{3}x\\\Rightarrow x=-3$

At $x=0$

$y=0+1\\\Rightarrow y=1$

Two points are $(-3,0),(0,1)$

The blue line represents the function

$5\geq y+x$

at $y=0$

$5=x$

at $x=0$

$y=5$

Two points are $(5,0),(0,5)$

The other two constraints are $x\geq 0$, $y\geq 0$. So, the point has to be in the first quadrant

From the graph it can be seen there are two points where the function will be maximum let us check them.

$(3,2)$

$7x-2y=7\times 3-2\times 2=17$

$(5,0)$

$7x-2y=7\times 5-2\times 0=35$

So, the maximum value of the function is $35$.