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Hatshy [7]
3 years ago
6

Explain how solving an equation with several variables is similar to and different from the process of solving equations in one

variable.
Mathematics
1 answer:
AysviL [449]3 years ago
4 0
It is similar in the sense that we add or subtract or multiply and divide the same thing to the opposite sides just like in one variable equations.and the difference really is that there is more that one variable and needs to be specified because there are several variables to choose from.....


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Two people bought gas .Each gallon of gas cost the same amount.The money that they spend in dollars is represented by the expres
nata0808 [166]
=75 he bought each person 10
8 0
3 years ago
#middleschoolstruggles Please help me with the page. Could u please include an answer and how u got it. Thanks
german
The pattern they're looking for in the uppermost question is 0,2,6,14,30,62.

The second problem shows the Fibonacci sequence.  Each number is the sum of the two numbers before it.  So:

2,3,5,8,13,21,34

34 are the number of miles she'll run on Week 8.  

The equation on the bottom right is M = 5p.  The first two numbers in the function table are 25 and 50.
6 0
3 years ago
The best player on a basketball team makes 80​% of all free throws. The​ second-best player makes 75​% of all free throws. The​
Artist 52 [7]

Answer:

Expected number of free throws in 60 attempts:

        Best player = 48

        2nd best player = 45

        3rd best player = 42

Step-by-step explanation:

Solution:-

- The probability that best player makes free throw, p1 = 0.8

- The probability that second-best player makes free throw, p2 = 0.75

- The probability that third-best player makes free throw, p3 = 0.70

- Total number of attempts made in free throws, n = 60.

- The estimated number of free throws that any player makes is defined by:

                      E ( Xi ) = n*pi

Where,           Xi = Player rank

                      pi = Player rank probability

- Expected value for best player making the free throws would be:

                    E (X1) = n*p1

                              = 60*0.8

                              = 48 free throws

- Expected value for second-best player making the free throws would be:

                    E (X2) = n*p2

                              = 60*0.75

                              = 45 free throws

- Expected value for third-best player making the free throws would be:

                    E (X3) = n*p3

                              = 60*0.70

                              = 42 free throws

8 0
3 years ago
-((-7) +(4)(-12)+(-3)(11)+(-2))
lakkis [162]

Answer:

<em>90</em>

Step-by-step explanation:

-((-7) + 4 × (-12) + (-3) × 11 + (-2))

-(-7 + 4 × (-12) + (-3) × 11 + (-2))

-(-7 - 48 - 33 - 2)

-(-90) → 90

Final Answer - 90

Hope this helped! :)

3 0
3 years ago
Read 2 more answers
Q8 Q3.) Solve the system by the substitution method.
inn [45]
Recall that (x+y)^2=x^2+2xy+y^2. So we can add twice the first equation to the second one to get

x^2+y^2+2xy=10+2\cdot3\iff(x+y)^2=16\implies x+y=\pm4

Since xy=3, we have y=\dfrac3x (x\neq0) so

x+y=x+\dfrac3x=\pm4\implies x^2\mp4x+3=0

If x+y=4, then

x^2-4x+3=(x-3)(x-1)=0\implies x=3,x=1\implies y=1,y=3

If x+y=-4, then

x^2+4x+3=(x+1)(x+3)=0\implies x=-1,x=-3\implies y=-3,y=-1

So the solution set is

(x,y)\in\{(-3,1),(1,3),(-1,-3),(-3,-1)\}
3 0
3 years ago
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