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Answer:
1. HA is equivalent to AAS when the triangle is a right triangle.
2. AM = BM, so the triangles are congruent by HL. CPCTC
3. The triangles are congruent by HL. CPCTC
Step-by-step explanation:
1. The acute angle of the triangle together with the right angle comprise two angles of the triangle. When two corresponding angles and a corresponding side (the side opposite the right angle) are congruent, the right triangles are congruent by the AAS theorem. (This can be referred to as the HA theorem.)
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2. CM = DM; MA = MB; ∠A = ∠C = 90°, so all of the requirements for the HL theorem are met. ΔCMA ≅ ΔDMB, so AC ≅ BD by CPCTC.
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3. TS = TV, TR = TR, ∠S = ∠V = 90°, so all requirements for the HL theorem are met. ΔTSR ≅ ΔTVR, so RS ≅ RV by CPCTC.
Answer:
Step-by-step explanation:
Use the Quadratic formula:
You can identify that, in this case:
Now you need to substitute these values into the formula:
Remember that:
Therefore,rewriting and simplifying, you get:
Then, you get the following roots:
First plane: 496x
<span>Second plane: 558( x - 1/2) </span>
<span>Equation: 496x = 558( x - 1/2) </span>
<span>Solving x = 9/2 , or x = 4.5 hours.
Hope this helps.</span>
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ok so put it like that and it will be correct.............................................................................(long pause)........................................................................................................... (thinks) I think that the right answer.
