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Licemer1 [7]
3 years ago
12

(x-2)(-5x^2+x)=(x)(-5x^2)+(x)(x)+(-2)(-5x^2)+(-2)(x) is an exsample of

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0

this is an example of linear equations is one variable

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Evaluate this expression by distributing the multiplication over division: 5 x (7+4)
Maru [420]

Answer:

I think you can write like this:

5 x (5+2+4)

OR

5 x 11

Step-by-step explanation:

My own knowladge

Hope it helps

Put a thanks

Thank you

6 0
3 years ago
Why does a logarithmic equation sometimes have an extraneous solution?
jonny [76]

The main reason behind this is using properties of logarithm .

like

when solving

  • log_2(x+2)+log_2(x-3)=3

There you use multiplication property and make addition to multiplication then you get extraneous solution because in plenty of cases they occur

like

  • (-2)²=(2)²

But

  • -2≠2

Same happens in case of logarithm

6 0
2 years ago
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A can of soup contains 1 1/4 cups. A serving is 1/2 of a cup. How many servings are in the
Bogdan [553]

Answer:

c 2 1/2

Step-by-step explanation:

3 0
2 years ago
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Giving brainliest if answer
Sedbober [7]

Answer:

4.9

Step-by-step explanation:

$70 times 7% = 4.9 (You can round it if you want)

5 0
2 years ago
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A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take
Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

<em>Null Hypothesis :- H₀ :  </em> (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

<u><em>Step(ii)</em></u>:-

Test statistic

                         t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }

                        t = \frac{517 -500}{\frac{90}{\sqrt{100} } }

                        t  =   1.717

<em>Level of significance</em>

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

<u><em>Conclusion</em></u>:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

3 0
3 years ago
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