1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paha777 [63]
2 years ago
13

If an object accelerates from rest, what will its velocity be after 1.3 s if it has a constant acceleration of 9.1 m/s^2?

Physics
1 answer:
HACTEHA [7]2 years ago
5 0

\text{Given that,}\\\\\text{Initial velocity,} ~v_0 = 0~ \text{m~s}^{-1}\\\\\text{Time,  t = 1.3~sec}\\\\\text{Acceleration, a = 9.1 m s}^{-2}\\\\\\\\\text{Velocity,}\\\\v = v_0  +at\\\\\implies v = 0 + 9.1 \times 1.3 = 11.83~~ \text{m~s}^{-1}

You might be interested in
How can we find the volume of a small pebble with the help of measuring cyilinder
ad-work [718]

We can find the volume of a small pebble with the help of measuring cylinder by using the water displacement method. <span>The </span>water displacement method<span> <span>is the process of measuring the volume of an irregularly shaped object by immersing it in water. </span></span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0
3 years ago
Please help me .finish this paper​
Evgesh-ka [11]

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>-</u><u>1</u><u>:</u><u>-</u>

\boxed{\sf \dfrac{10\times 1000}{60\times 60}}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>2</u>

\boxed{\sf Sodium\:and\:Potassium}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>3</u>

\boxed{\sf 320m}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>4</u>

\boxed{\sf Rough\:tiles\:are\:used\:in\:bathroom}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>5</u>

\boxed{\sf Mg_3N_2}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>6</u>

\boxed{\sf Grapes\:and\:Rambutan}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>7</u>

\boxed{\sf {}^{}_{}N}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>8</u>

\boxed{\sf Galactuse}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>9</u>

\boxed{\sf Y-X}

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>10</u>

\boxed{\sf Cell\:wall}

7 0
3 years ago
A missile is moving 1350 m/s at a 25.0° angle. It needs to hit a target 23,500 m away in a 55.0° direction in 10.20 s. What is d
QveST [7]

Answer:

  The target's velocity is about 1320 m/s in the direction 265.7°.

Explanation:

In order for there to be a collision between missile and target, we must have ...

  (target starting position) + (target movement) = (missile movement)

assuming the missile starts from the origin of all measurements. The missile moves 10.2 seconds before impact, so moves a distance of ...

  (10.2 s)(1350 m/s) = 13,770 m

__

We are interested in the target movement, so we can solve for that:

  (target movement) = (missile movement) - (target starting position)

In terms of meters, this is ...

  (target movement) = 13770∠25° - 23500∠55° ≈ 13467.74∠-94.3°

The target covers this distance in the same 10.2 seconds before collision, so its speed is (13467.74 m)/(10.2 s) ≈ 1320.4 m/s.

As a positive angle, the target's direction is ...

  -94.3° +360° = 265.7°

The direction of the target's velocity is 265.7°.

_____

If you're calculating this by hand, there are a couple of ways you can do it. You can convert to rectangular coordinates and back (perhaps least confusing), or you can use the law of cosines to solve the triangle, then translate angles back to the x-y coordinate plane.

Using rectangular coordinates, we have ...

  13770∠25° = 13770(cos(25°), sin(25°)) ≈ (12479.9, 5819.45)

  23500∠55° = 23500(cos(55°), sin(55°)) ≈ (13479.0, 19250.1)

Then the difference is ...

  (12479.9, 5819.45) -(13479.0, 19250.1) ≈ (-999.188, -13430.6)

and the (3rd-quadrant) angle is ...

  target direction = arctan(-13430.6/-999.188) ≈ -94.3° = 265.7°

__

The target's speed is found by dividing the distance it covers by the time it takes.

  √(13430.6² +999.188²)/10.2 ≈ 1320.36 . . . m/s

3 0
3 years ago
The organ procurement and transplant network (OPTN) was established by?
damaskus [11]
The answer to that would be A. the national organ transplant Act of 1984 the goals of the OPTN  are to increase the number of and access to transplants, improve survival rates after transplantation, and to promote patient safety and efficient management of the system.
5 0
3 years ago
Read 2 more answers
Just say the letter of answer asap
kap26 [50]

answer  for number nine is C

Convergent boundaries: where two plates are colliding. Subduction zones occur when one or both of the tectonic plates are composed of oceanic crust.

Divergent boundaries – where two plates are moving apart. ...


Transform boundaries – where plates slide passed each other.

answer for number eight is d.

hope this help you

3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the symbol name?
    10·1 answer
  • You are driving home from school steadily at 91 km/h for 160 km . It then begins to rain and you slow to 64 km/h instantly. You
    13·1 answer
  • Usually, when the temperture is increased l, what will happen to the ratevof dissolving?
    14·1 answer
  • How does energy affect a wave​
    6·1 answer
  • An object is projected straight upward with an initial speed of 25.0 m/s
    7·1 answer
  • a dad expends 200 joules of work pushing a stroller up a hill. he produces 125 j of work. how efficient is he being?
    6·1 answer
  • The skateboarder weighs 75 kilogram. Calculate the potential energy of the skateboarder sliding on the track when his height abo
    11·2 answers
  • If i eat myself will I get twice as big or disappear completely?
    14·1 answer
  • A 1kg mass is moving at 1m/s. What is its kinetic energy?
    12·1 answer
  • Which best describes the results of Becquerel’s experiments?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!