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Evgesh-ka [11]
3 years ago
12

A force of 6600 N is exerted on a piston that has an area of 0.010 m2

Physics
1 answer:
sveticcg [70]3 years ago
4 0

Answer:

Choice A: approximately 0.015\; \rm m^2, assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

By Pascal's Principle, because the first piston exerted a pressure of 6.6\times 10^{5}\; \rm N \cdot m^{-2} on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be 6.6\times 10^{5}\; \rm N \cdot m^{-2}. In other words:

P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

To achieve a force of 9.900 \times 10^3\; \rm N, the surface area of the second piston should be:

\displaystyle A_2 = \frac{F_2}{P_2} = \frac{9.900\times 10^{3}\; \rm N}{6.6\times 10^5\; \rm N \cdot m^{-2}} \approx 0.015\; \rm m^{2}.

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Calculate the torques about pivot P provided by the forces shown in the Figure 3, if L = 4.5 m
g100num [7]

The definition of torque of a force we can find the total torque on the bar is

           τ = 246.2 N m

The torque of a force is defined by the relation

         τ = F x r

where the bold letters indicate vectors, τ is the torque, f the force, and r the distance from the pivot point.

We can calculate the magnitude of this expression

       τ = F r sin θ

where in the angle between the forces and the candidate

In this case, we have five forces

  • the force at point P does not create torque since its distance is zero.
  • The force applied to the end of the bar, the angle is zero and the sine value zero.

The other forces create a torque:

F₁ =   80 N, the distance is x₁ = 0.5L,  θ₁ = 37º

F₂ = -60 N, the distance is x₂ = 0.5L, angle θ = 90º

F₃ =  70 N the distance is x₃ = L, angles θ = 30º

with respect to the vertical, this angle with respect to the horizontal is

         θ’ = θ + 90

         θ‘ = 30+ 90

         θ₃' = 120º

substitute

         τ = F₁ x₁ sin θ₁ + F₂ x₂ sin θ₂ + F₃ x₃ sin  θ₃'

let's calculate

          τ = 80 0.5L sin 37 - 60 0.5L sin 90 + 70 L sin 120

          τ = 54.7L

indicate that the length of the bar is L + 4.5 m

           τ = 54.7  4.5

           τ = 246.2 Nm

Using the defined torque we can find the total torque on the bar is

           τ = 246.2 N m

Learn more about torque here:

brainly.com/question/6855614

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