3 years ago

36 − [18 − {14 − (15 − 4 ÷2 ×2)}]

Mathematics

1 answer:

muminat3 years ago

5 0

Answer: 21

Step-by-step explanation:

have a good day! :)

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(28 and 29) I really need help

scoundrel [369]

Answer:

28 is 11/60

29 is 7/30

Step-by-step explanation:

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3 years ago

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-9 is the answer

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<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

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3 years ago

Determine if the triangles, ΔSXC and ΔDXY, are similar. If so, identify the similarity criterion.

Lesechka [4]

THE ANSWER IS B SAS SIMILARITY

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3 years ago

Read 2 more answers

David rented a truck for one day there was a base base fee of $19.99 and there was an additional charge of $.84 for each mile dr

MissTica

196 Miles

184.63-19.99=164.64

164.64/.84= 196

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3 years ago

36 − [18 − {14 − (15 − 4 ÷2 ×2)}]​

36 − [18 − {14 − (15 − 4 ÷2 ×2)}]