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3 years ago

ASAPPP TIMED QUIZ

Mathematics

2 answers:

Serjik [45]3 years ago

8 0

I think they answe is either c or d probably c

Lemur [1.5K]3 years ago

5 0

Answer:c.-2.5 is answer

sorry I cannot do this.I didn't found z over here. I think question is

.25^(z+ 4) = 125

5^(2z+8)=5³

again

2z+8=3

2z=3-8

2z=-5

z=-5/2=-2.5

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I really need help fast

xenn [34]

Answer:

Tom jogged farther.

Step-by-step explanation:

2 1/2 + 3 1/8 = 5 5/8 5 6/8 would be equalt to 5 3/4 but since it isn't 5 3/4 is farther.

Tom jogged 1/8 farther.

6 0

3 years ago

Approximately 14 percent of the population of Arizona is 65 years or older. A random sample of five persons from this population

Andreas93 [3]

Answer:

A)0.8533

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are 65 or older, or they are not. The probability of a person being 65 or older is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

14 percent of the population of Arizona is 65 years or older.

This means that $p = 0.14$

A random sample of five persons from this population is taken.

This means that $n = 5$

The probability that less than 2 of the 5 are 65 years or older is :

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.14)^{0}.(0.86)^{5} = 0.4704$

$P(X = 1) = C_{5,1}.(0.14)^{1}.(0.86)^{4} = 0.3829$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.4704 + 0.3829 = 0.8533$

So the correct answer is:

A)0.8533

3 0

3 years ago

What is the solution of x/2=6

Lina20 [59]

Answer:

Step-by-step explanation:

12/2=6

replace x with 12

4 0

3 years ago

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Brandon sights a helicopter above a building that is 200 feet away at an angle of elevation of 30 degrees. To the nearest foot,

Firlakuza [10]

The problem says that Brandon sights a helicopter above a building that is 200 feet away at an angle of elevation of 30 degrees. So, you can calculate the height asked, by following this procedure:

Tan(α)=Opposite leg/Adjacent leg

α=30°
Opposite leg=x
Adjacent leg=200 feet

When you substitute these values into the formula above (Tan(α)=Opposite leg/Adjacent leg), you have:

Tan(α)=Opposite leg/Adjacent leg
Tan(30°)=x/200

You must clear "x":

x=200xTan(30°)

Therefore, the value of "x" is:

x=115 feet

How high above the ground the is the helicopter?

The answer is: 115 feet

4 0

3 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = 100m.

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = 4800 m²

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

2 years ago

Read 2 more answers