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3 years ago

Help me please its confusing pleasee

Mathematics

1 answer:

bezimeni [28]3 years ago

4 0

Answer:

a) -8x³+x²+6x

d) 16x²-9

Step-by-step explanation:

a) -2x(x+4x²)+3(x²+2x)

Expand each bracket:

-2x(x+4x²)

As the -2x is on the outside of the bracket, you have to times everything inside the bracket by -2x.

-2x times x equals -2x²

-2x times 4x² equals -8x³

Then we expand the other bracket:

3(x²+2x)

3 times x² equals 3x²

3 times 2x equals 6x

We then put all of it together:

-2x²-8x³+3x²+6x

Collect like terms:

-8x³+x²+6x

b) (4x-3)(4x+3)

We will use the FOIL method:

F-First

O-outer

I-Inner

L-Last

Times the first two terms in each bracket:

4x times 4x equals 16x²

Times the outer terms in the bracket:

4x times 3 equals 12x

Times the inside terms in the bracket:

-3 times 4x equals -12x

Times the last terms in the bracket:

-3 times 3 equals -9

Put it together:

16x²+12x-12x-9

The 12x and -12x cancel out to leave 16x²-9

Hope this helps :)

You might be interested in

How many cubes with side lengths of 1/3 cm does it take to fill the prism?

user100 [1]

Answer:

The number of cubes that fill the prism is 24

Step-by-step explanation:

Given as :

The length of cube (l) = $\frac{1}{3}$ cm

The length of prism (L) = 1 cm

The width of prism (w) = 2 $\frac{2}{3}$ = $\frac{8}{3}$ cm

The height of prism (h) = $\frac{2}{3}$ cm

Let the number of cubes that fill the prism = x

Now, Volume of cube with length (l) = l³ cm³

Or, Volume of cube with length (l) = $(\frac{1}{3})^{3}$ cm³

Or, Volume of cube with length (l) = $(\frac{1}{27})$ cm³

Again , Volume of prism = $\frac{1}{2}\times Length \times width \times height$

Or, Volume of prism = $\frac{1}{2}\times 1 \times \frac{8}{3} \times \frac{2}{3}$

Or, Volume of prism = $(\frac{8}{9})$ cm³

<u>So , The number of cubes to fill prism </u>

The number of cubes × Volume of cube = Volume of prism

Or, x × $(\frac{1}{27})$ cm³ = $(\frac{8}{9})$ cm³

or x = $\frac{8\times 27}{9}$ = 24

Hence The number of cubes which fill the prism is 24 Answer

8 0

3 years ago

8. A recipe for 24 cookies calls for 6 tablespoons of sugar. If you make 36 cookies and use 10 tablespoons, will the cookies tas

Salsk061 [2.6K]

No, because they wouldn't contain the same amount of sugar per cookie
for the first recipe - 24 cookies with 6 tablespoons
thats 6/24 so 0.25 tablespoons of sugar per cookie
for the second recipe - 36 cookies with 10 tablespoons
thats 10/36 so 0.276 tablespoons per cookie
the cookies in the second recipe would be slightly sweeter than the cookies in the first

3 0

3 years ago

Write 2^8 * 8^2 * 4^-4 in the form 2^n

Eva8 [605]

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

<h3>What are exponential forms?</h3>

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

<u>For example:</u>

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

a is the base, and
4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power.

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

$\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }$

$\mathbf{= 2^8\times (2^6) \times (2^{-8}) }$

$\mathbf{= 2^{8+6+(-8)}}$

$\mathbf{= 2^{6}}$

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

Learn more about exponential forms here:

brainly.com/question/8844911

#SPJ1

4 0

2 years ago

The boundary line on the graph represents the equation

QveST [7]

5x+26< 6 maybe this is the answer

4 0

3 years ago

Read 2 more answers

Solve for m 1/C+1/m=1/z

9966 [12]

Answer: " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given: 1/C + 1/m = 1/z ; Solve for "m".

Subtract "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C ;

to get: 1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get: zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24

zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
___________________________________________________

4 0

3 years ago