if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed
1 answer:
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Answer:
wavelength = 0.968 m
frequency = 39.02 Hz
Explanation:
given data
mass = 0.0127 kg
force = 9.33 N
length = 1.93 m
to find out
wavelength and Frequency
solution
we know here linear density that is
linear density = .........1
linear density =
linear density = 6.5803 × kg/m
so
wavelength will be here
wavelength = ..............2
here n = 4 for forth harmonic
wavelength =
wavelength = 0.968 m
and
frequency will be for 4th normal mode of vibration is
frequency = ..........3
frequency =
frequency = 1.036269 × 37.654594
frequency = 39.02 Hz
Answer:
a) E = 2.7x10⁶ N/C
b) F = 54 N
Explanation:
a) The electric field can be calculated as follows:
<u>Where</u>:
K: is the Coulomb's constant = 9x10⁹ N*m²/C²
q: is the charge
d: is the distance
Now, we need to find the electric field due to charge 1:
The electric field due to charge 2 is:
The electric field at a point midway between them is given by the sum of E₁ and E₂ (they are in the same direction, that is to say, to the right side):
Hence, the electric field at a point midway between them is 2.7x10⁶ N/C to the right side.
b) The force on a charge q₃ situated there is given by:
Therefore, the force on a charge q₃ situated there is 54 N.
I hope it helps you!
Answer:
Resultant amplitude is 0.53 m.
Explanation:
Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.
The resulting amplitude of any two waves is given by the relation :
A =
Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.
According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,
A =
A =
A = 0.63 m