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Scilla [17]
3 years ago
14

A wave of amplitude 0.4 m interferes with a second wave of amplitude 0.23 m traveling in the same direction. What is the largest

resultant amplitude that can occur? Answer in units of m
Physics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

Resultant amplitude is 0.53 m.

Explanation:

Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.

The resulting amplitude of any two waves is given by the relation :

A = \sqrt{A_{1} ^{2} + A_{2} ^{2} + 2A_{1}A_{2}\cos x   }

Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.

According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,

A = \sqrt{0.4^{2} + 0.23^{2} + 2\times 0.4\times 0.23\times cos 0   }

A = \sqrt{0.16 + 0.053 + 0.184   }

A = 0.63 m

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<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}

=> R_{X} = \frac{R_1 * R_2}{R_1 + R_2}             ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

R_{X} = \frac{3 * 7}{3 + 7}

R_{X} = \frac{21}{10}

R_{X} = 2.1Ω

(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

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