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Scilla [17]
3 years ago
14

A wave of amplitude 0.4 m interferes with a second wave of amplitude 0.23 m traveling in the same direction. What is the largest

resultant amplitude that can occur? Answer in units of m
Physics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

Resultant amplitude is 0.53 m.

Explanation:

Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.

The resulting amplitude of any two waves is given by the relation :

A = \sqrt{A_{1} ^{2} + A_{2} ^{2} + 2A_{1}A_{2}\cos x   }

Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.

According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,

A = \sqrt{0.4^{2} + 0.23^{2} + 2\times 0.4\times 0.23\times cos 0   }

A = \sqrt{0.16 + 0.053 + 0.184   }

A = 0.63 m

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. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in
kupik [55]

Answer:

(c) 16 m/s²

Explanation:

The position is r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}.

The velocity is the first time-derivative of <em>r(t).</em>

<em />v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}<em />

The acceleration is the first time-derivative of the velocity.

a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}

Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,

a = -16\hat{j}

Its magnitude is 16 m/s².

4 0
3 years ago
If you push any floating object down from equilibrium and release it, it bobs up and down. That looks like an oscillation, so le
GarryVolchara [31]

Answer:

  F_{y} = ( ρ_fluid g A) y

Explanation:

This exercise can be solved in two parts, the first finding the equilibrium force and the second finding the oscillating force

for the first part, let's write Newton's equilibrium equation

        B₀ - W = 0

        B₀ = W

        ρ_fluid g V_fluid = W

the volume of the fluid is the area of ​​the cube times the height it is submerged

      V_fluid = A y  

For the second part, the body introduces a quantity and below this equilibrium point, the equation is

        B - W = m a

        ρ_fluid g A (y₀ + y) - W = m a

        ρ_fluid g A y + (ρ_fluid g A y₀ -W) = m a

       ρ_fluid g A y + (B₀-W) = ma

the part in parentheses is zero since it is the force when it is in equilibrium

      ρ_fluid g A y = m a

      this equation the net force is

      F_{y} = ( ρ_fluid g A) y

we can see that this force varies linearly the distance and measured from the equilibrium position

8 0
3 years ago
A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic ener
Mademuasel [1]

The kinetic energy gained by the air molecules is 0.0437 J                

<h3 />

Given:

Mass of a coffee filter, m = 1.5 g

Height from which it is dropped, h = 3 m

Speed at ground, v = 0.7 m/s

Initially, the coffee filter has potential energy. It is given by :

P =mgh

P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m

P = 0.0441 J

Finally, it will have kinetic energy. It is given by :

E= \frac{1}{2} mv^{2}

E= \frac{1}{2}×1.4 × 10⁻³ × (0.7)²

E = 0.000343 J

The  kinetic energy Kair did the air molecules gain from the falling coffee filter is :

E = 0.000343 -  0.0441

  = 0.0437 J

So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

Learn more about kinetic energy here:

brainly.com/question/8101588

#SPJ4

8 0
2 years ago
A street light is on top of a 8 foot pole. Joe,
zubka84 [21]
8/4 = y/y-x

8y - 8x  = 4y

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y = 8

Hope this helps
5 0
3 years ago
Whitch two options are forms of kinetic energy?
valentina_108 [34]

Answer:the witch has nothing to do with the problem

Explanation:

7 0
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