Answer:
The pressure of a gas increases in a closed container if the volume of the gas decreases. Pressure and volume have inverse relationship which means if one increases the other decreases and vice versa. If pressure increases, volume of a gas decreases because there are a lot of empty spaces present between gas particles which are filled when gas particles come closer to each other due to pressure applied.
Gamma rays because microwaves, visible light and radio waves wouldn’t come in handy if an astronomer would want to study the composition of planets and stars.
Deltas and sand dunes form from erosion
<span>a river carrying dirt into a lake is a example of water erosion
</span>
fossils can tell us about environments
when the oceanic and continental plate collide, the oceanic plate sinks below the continental plate
a footprint is a trace fossil
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The answer is C, twisted ladder

<u>Aerobic </u><u>respiration </u>:- Aerobic respiration is process of respiration in which complete oxidation of glucose takes place in the presence of oxygen
<u>That </u><u>is</u><u>, </u>
<u>Aerobic </u><u>respiration </u><u>is </u><u>takes </u><u>place </u><u>in </u><u>four </u><u>stages </u><u>:</u><u>-</u>
- <u>Glycolysis</u>
- <u>The </u><u>link </u><u>reaction </u>
- <u>The </u><u>Krebs </u><u>cycle </u>
- <u>Oxidative </u><u>phosphorylation </u>
In aerobic respiration, Glucose with 6 carbon atoms broken into 2 pyruvic acid each with 3 carbon atom and produces water + CO2 + energy.
<h3><u>Whereas</u><u>, </u></h3>
<u>Anaerobic </u><u>respiration </u>:- is the process of respiration in which incomplete oxidation of glucose takes place in the absence of oxygen
The end products of glucose in anaerobic respiration is
- <u>In </u><u>human </u><u>muscles</u><u>, </u><u> </u><u>Lactic </u><u>acid </u><u>+</u><u> </u><u>Energy </u>
- <u>In </u><u>yeast</u><u>, </u><u>Ethanol </u><u>+</u><u> </u><u>CO2</u><u> </u><u>+</u><u> </u><u>Energy </u>
<u>Hence</u><u>, </u><u>Option </u><u>D </u><u>is </u><u>the </u><u>correct </u><u>answer</u><u>.</u>