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2 years ago

(awarding brainliest) PLS HELP ME i’m not that smart.

Mathematics

1 answer:

sleet_krkn [62]2 years ago

8 0

Answer:

1. 43.98

2. 28.27

3. 7.85

Step-by-step explanation:

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The sum of three consecutive is 267. What is the largest integer

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Consecutive means in order. So let's call the first integer x. The next number in line would be x+1 and the largest integer would be x+2. Let's prove that so you're not confused. If x is 3, then x+1 is 4 (next in line), and x+2 is 5 next after that. See? So if we add all those together we set them equal to 267 and solve for x: x + x+1 + x+2 = 267. Combining like terms gives us 3x + 3 = 267 and 3x = 264. Now dividing both sides by 3 we get that x = 88. That's the smallest integer; the largest is found by adding 88 + 2 which is 90. So that means that the numbers are 88, 89, 90, and that adding them up = 267. Let's check that now: 88+89+90=267 so we're good.

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2 years ago

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2 years ago

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events A and B are independent.

Step-by-step explanation:

The events are defined as follows:

A = a student in the class has a sister

B = a student has a brother

The information provided is:

N = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event X provided that another event Y has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events X and Y are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event A and B as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of B given A as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events A and B are independent.

6 0

3 years ago