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frutty [35]
3 years ago
10

12. A roller coaster is sitting at the top of a 80 m hill and has 94646J. What is its mass?

Physics
1 answer:
yulyashka [42]3 years ago
3 0

Answer:

Mass, m = 120.72 kg.

Explanation:

<u>Given the following data;</u>

P.E = 94646J

Height, h = 80m

We know that acceleration due to gravity is 9.8m/s²

Since the roller coaster is sitting at the top of a hill, it simply means it possesses energy due to its position.

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where, P.E represents potential energy measured in Joules.

  • m represents the mass of an object.
  • g represents acceleration due to gravity measured in meters per seconds square.
  • h represents the height measured in meters.

To find its mass?

<em>Substituting the values into the equation, we have;</em>

94646 = m*9.8*80

94646 = m*784

m = \frac {94646}{784}

Mass, m = 120.72 kg.

<em>Therefore, the mass of the roller coaster is 120.72 kilograms. </em>

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a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the
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Explanation:

Given;

initial speed, u = 70 mph

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The average speed of the car is calculated as;

v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph

Therefore, the average speed of the car is 170 mph.

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two soccer players run toward each other. one player has a mass of 85 kg and runs west with a speed of 8 m/s, while the other ha
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Answer:

Total momentum, p = 55 kg-m/s

Explanation:

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

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Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

p=m_1v_1+m_2v_2

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A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc
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Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

<u>Given the following data;</u>

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

<em>Angle = 41.7° Northeast.</em>

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

<em>Vr = 7.08m/s</em>

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