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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!

Physics

2 answers:

Svetllana [295]3 years ago

8 0

A.Ganerators

is the answer

shtirl [24]3 years ago

3 0

Agree with previous answer.

A. Generators

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You can get an object in motion by a push or pull!

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3 years ago

A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas

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Answer:

ΔP = (640 N/cm^2)

Explanation:

Given:-

- The volume increase, ΔV/V0 = 4 ✕ 10^-3

- The Bulk Modulus, B = 1.6*10^9 N/m^2

Find:-

Calculate the force exerted by the moonshine per square centimeter

Solution:-

- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

B = ΔP / [(ΔV/V)]

- Now rearrange the above relation and solve for ΔP or force per unit area.

ΔP = B* [(ΔV/V)]

- Plug in the values:

ΔP = (1.6*10^9)*(4 ✕ 10^-3)

ΔP = 6400000 N/m^2

- For unit conversion from N/m^2 to N/cm^2 we have:

ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

ΔP = (640 N/cm^2)

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3 years ago

Suppose there are 10,000 civilizations in the Milky Way Galaxy. If the civilizations were randomly distributed throughout the di

vekshin1

Here is the full question

Suppose there are 10,000 civilizations in the Milky Way Galaxy. If the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization?

(Hint: Start by finding the area of the Milky Way's disk, assuming that it is circular and 100,000 light-years in diameter. Then find the average area per civilization, and use the distance across this area to estimate the distance between civilizations.)

Answer:

1000 light-years (ly)

Explanation:

If we go by the hint; The area of the disk can be expressed as:

$A = \pi (\frac{D}{2})^2$