Answer:
A light beam incident on a diffraction grating consists of waves with two different wavelengths. The separation of the two first order lines is great if
the dispersion is great
Answer:
The speed of the riders on the Singapore Flyer is approximately 0.262 m/s
Explanation:
The dimensions of the tallest Ferris wheel in the world are;
The diameter of the Ferris wheel, D = 150 m
The tine it takes the Ferris wheel to make a full circle, T = 30 minutes = 30 min × 60 s/min = 1,800 seconds
The angular velocity of the Ferris wheel, ω = 2·π/T
The linear velocity of the Ferris wheel, v = r·ω = The speed of the riders
Where;
r = The radius of the Ferris wheel = D/2
D = 150 m
∴ r = 150 m/2 = 75 m
∴ v = r·2·π/T
∴ v = 75 m × 2 × π/(1,800 s) ≈ 0.262 m/s
The speed of the riders on the Singapore Flyer, v ≈ 0.262 m/s
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />
According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.
Now, in this case we are on Earth, so the gravity value is 
Note the objects experience the acceleration of gravity regardless of their mass.
Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely true on Earth, unless the following condition is fulfiled:
If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at and hit the ground at approximately the same time.
Answer:
304.86 metres
Explanation:
The x and y cordinates are 
and 
respectively
The horizontal distance travelled, 
Making t the subject, 
Since 
, we substitute t with the above and obtain
Making d the subject we obtain
d=304.8584
d=304.86m
The maximum height to which the ball attain before falling back down is 1147.96 m
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Initial velocity (u) = 150 m/s
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration due to gravity (g) = 9.8 m/s²
- Maximum height (h) =?
<h3>How to determine the maximum height </h3>
The maximum height reached by the ball can be obtained as illustrated below:
v² = u² – 2gh (since the ball is going against gravity)
0² = 150² – (2 × 9.8 × h)
0 = 22500 – 19.6h
Collect like terms
0 – 22500 = –19.6h
–22500 = –19.6h
Divide both side by –19.6
h = –22500 / –19.6
h = 1147.96 m
Thus, the maximum height reached by the ball is 1147.96 m
Learn more about motion under gravity:
brainly.com/question/22719691
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