Answer:
v = 6.05 m/s
Explanation:
The mass of the brick, M = 21 kg
The velocity of the brick, U = 6.1 m/s
The mass of the cart, m = 2.9 kg
The velocity of the cart, u = 0.26 m/s
The combined mass of the brick and the cart, v = ?
According to the law of conservation of linear momentum,
Combined final momentum = sum of the initial momentum
(M + m)v = MU + mu
v = MU + mu / M + m
= 21 x 6.1 + 2.1 x 0.26 / (21 + 0.26)
= 6.05 m/s
Hence, the combined velocity of the cart and the brick is, v = 6.05 m/s
Answer:
A. As the ropes are horizontal the child has travelled 2m of vertical displacement from his lowest position.
Gpe @ A=mgh=40*9.81*2=784.8J
B. At 30degree vertical angle the vertical displacement from lowest position is given by
2-2cos(30)=2-1.73=0.27m
Gpe @B= 40*9.81*0.27=106 J
C: at the bottom of circular arc it's Gpe is zero relative to lowest position as bottom of arc itself is lowest position.
Energy that transfers through the medium
If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.
Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.
A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.
To know more about acceleration refer to: brainly.com/question/14468548
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