1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maru [420]
3 years ago
11

At which position does the diver have the most gravitational potential energy

Physics
2 answers:
marta [7]3 years ago
4 0
Directly vertical. The surface area is the smallest, allowing for the water upthrust to be kept to a minimum, whilst the mass is the same, which keeps the same weight and gravitational pull.
Ray Of Light [21]3 years ago
3 0
Potantial energy formula = m.g.h
m: mass
g: gravitational acceleration
h: height

m and g are the same. So, we must to look at to the height. At the vertical position, the potantional energy increase. 

When the h increase, the energy will increases.
You might be interested in
I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app
Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

6 0
3 years ago
Pure water has a pH of 7. Pure water _______. A. Is a neutral substance B. Could be either an acid or a base C. Is a base D. Is
Hoochie [10]

A. is a neutral substance a pH of 7 describes something of neutral pH where anything less than 7 is an acid and higher is a base

5 0
3 years ago
Read 2 more answers
A 2.20 kg mass is at the origin. A
Karolina [17]

Answer:

0

Explanation:

F1 = G•2.2•4.66/3² (pointed right)

F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

3 0
2 years ago
Read 2 more answers
What is acceleration produced by a force of 12 newton exerted on an object of mass 3kg​
jarptica [38.1K]

Answer:

a=F/m

a=12N/3kg  (here newton can be written as kgm/s^2 so kg will be cancelled)

a=4m/s^2

Explanation:

3 0
3 years ago
in the system to the right, the pulleys are frictionless and the system hangs in equilibrium. Determine the values of each of th
irga5000 [103]
Look up pulleys problem through Khan academy and a video should pop up with a problem similar and you should be able to walk through it .
4 0
2 years ago
Other questions:
  • The interference of two sound waves of slightly different frequencies produces
    5·2 answers
  • The bar graph below shows the number of tickets sold for each of the seating sections in a baseball stadium.
    7·2 answers
  • A 150 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. Calculate the magn
    14·1 answer
  • What’s the answer???
    10·1 answer
  • What branch of science does anatomy fall under?
    11·1 answer
  • An object is travelling in a straight line. The diagram is the speed-time graph for
    15·1 answer
  • They want a mixture of 150 grams of water at 60 degrees Celsius, using hot water at 90 degrees Celsius and cold water at 14 degr
    5·1 answer
  • What is the full moon that occurs during the autumn equinox called?
    13·1 answer
  • 1 point
    8·1 answer
  • Why do some quasars have red shifts greater than 1?.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!