5. m∠C = 95°
6. m∠C = 70°
7. The other acute angle in the right triangle = 70°
8. m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 110°
11. m∠B = 70°
12. m∠Z = 70°
<h3>What are Triangles?</h3>
A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:
- Isosceles triangle: has 2 equal base angles.
- Equilateral triangle: has three equal angles, each measuring 60 degrees.
- Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.
5. m∠C = 180 - 50 - 35 [triangle sum theorem]
m∠C = 95°
6. m∠C = 180 - 25 - 85 [triangle sum theorem]
m∠C = 70°
7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]
The other acute angle = 70°
8. m∠C = 180 - 55 - 55 [isosceles triangle]
m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 50 + 60
Measure of the exterior angle at ∠C = 110°
11. m∠B = 115 - 45
m∠B = 70°
12. m∠Z = 180 - 35 - 75
m∠Z = 70°
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Answer:
12 m
Step-by-step explanation:
Given that the design, ABCD, was dilated to get a photocopy, EFGH, a scale factor or ratio was multiplied by the original lengths of the design to get the new measurement of the photocopy.
Thus, we are given the ratio, CD:GH = 2:3.
This means, any of the corresponding lengths of both figures would be in that same ratio.
Using the ratio of the design to the photocopy, 2:3, we can find the length of side EH of the photocopy.
The corresponding side of EH in the design is AD = 8m. Thus, AD to EH = ⅔
Cross multiply
Divide both sides by 2 to make EH the subject of formula
The length of side EH = 12 m
Possibly 5?
50 m
—
10 s
Is the s speed?
The question isn’t specific enough.