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astra-53 [7]
3 years ago
11

Using the equation below, calculate the percent yield of H3PO4 if an experiment that started with 12.98 grams of HCl and excess

Na3PO4 yielded 8.42 g of H3PO4. Please round to the nearest 0.01 and remember units and substance.
Na3PO4 + HCl --> NaCl + H3PO4
Chemistry
1 answer:
ser-zykov [4K]3 years ago
7 0
U are in my class because the teacher gave the same question I will tell aleveryone that you are cheat in g
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It is 79 - + 3 = 76 electrons.
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An equilibrium mixture of PCl 5 ( g ) , PCl 3 ( g ) , and Cl 2 ( g ) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 To
antoniya [11.8K]

Answer: The new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

Explanation:

For the given chemical reaction:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of K_p for above reaction follows:

K_p=\frac{P_{PCl_5}}{P_{PCl_3}\times P_{Cl_2}}         ........(1)

We are given:

P_{PCl_5}=217.0torr

P_{PCl_3}=13.2torr

P_{Cl_2}=13.2torr

Putting values in above equation, we get:

K_p=\frac{217.0}{13.2\times 13.2}\\\\K_p=1.24

Now we have to calculate the new partial pressure of Cl_2.

P_{PCl_5}+P_{PCl_3}+P_{Cl_2}=P_{Total}

217.0torr+13.2torr+P_{Cl_2}=263.0torr

P_{Cl_2}=32.8torr

The reaction is re-established and proceed to right direction by Le-Chatelier's principle to cancel the effect of addition of Cl_2.

Now, the equilibrium is shifting to the reactant side. The equation follows:

                       PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:             13.2         32.8            217.0

At eqm:         13.2-x      32.8-x         217.0+x

Putting values in expression 1, we get:

1.24=\frac{(217.0+x)}{(13.2-x)(32.8-x)}\\\\x=40.4,6.38

Neglecting the 40.4 value of 'x'  because pressure can not be more than initial partial pressure.

Thus, the value of 'x' will be, 6.38 torr.

Now we have to calculate the new partial pressures after equilibrium is reestablished.

Partial pressure of PCl_5 = (217.0+x) = (217.0+6.38) = 223.4 torr

Partial pressure of PCl_3 = (13.2-x) = (13.2-6.38) = 6.82 torr

Partial pressure of Cl_2 = (32.8-x) = (32.8-6.38) = 26.4 torr

Hence, the new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

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3 years ago
Enter an abbreviated electron configuration for magnesium: Express your answer in complete form, in order of increasing energy.
stiks02 [169]

Answer:

1s2, 2s2,2p6,3s2

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It takes 412. KJ/mol to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrog
olga_2 [115]

Answer:

The maximum wavelength of light for which a carbon-hydrogen single bond could be broken by absorbing a single photon = 290 nm

Explanation:

                  So to break a single C - H bond require = \frac{412}{6.023 X (10)^{23} }

                           = 6.84 x 10⁻¹⁹ joule

Find the wavelength of a photon we use E = hν

                                                             ⇒    E = \frac{hc}{Wavelength}

                   Where h = Planck's constant = 6.626 x 10⁻³⁴ J.K⁻¹.Mole⁻¹

                               c = speed of light = 3 x 10⁸ m/sec

                                                           Wavelength = \frac{6.626 X 10^{-34} X 3 X 10^{8} }{6.84 X10^{-19}  }

                                                                                 = 2.9 x 10⁻⁷ m

                                                                                 = 290 nm

                                           ∵ 1 nm = 10⁻⁹ m

                         

7 0
3 years ago
Nvm i dont have any questions
gregori [183]

Answer:

well if you ever do neeed help im here

Explanation:

5 0
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