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Inga [223]
3 years ago
7

Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl. Calculate the pH after the following volumes of titrant have

been added. You may want to reference (Pages 729 - 739) Section 17.3 while completing this problem.

Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

you have not specify the volumes of HCL to be added, but I will show you the necessary steps for 0 and 10 ml of HCl.

If you need any other amount you just have to follow the same steps.

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To determine the freezing point depression of a LiCl solution, Toni adds 0.411 g of LiCl to the sample test tube along with 19.7
Cerrena [4.2K]

Answer:

LiCl = 0.492 m

Explanation:

Molal concentration is the one that indicates the moles of solute that are contained in 1kg of solvent.

Our solute is lithium chloride, LiCl.

Our solvent is distilled water.

We do not have the mass of water, but we know the volume, so we should apply density to determine mass.

Density = mass / volume

Density . volume = mass

1 g/mL . 19.7 mL = 19.7 g

We convert g to kg → 19.7 g . 1 kg / 1000g = 0.0197 kg

Let's determine the moles of LiCl

0.411 g . 1 mol / 42.394 g = 9.69×10⁻³ moles

Molal concentration (m) = 9.69×10⁻³ mol / 0.0197 kg → 0.492 m

7 0
3 years ago
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kap26 [50]

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7 0
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3. Write a hypothesis that explains your inference about the acidity of the paper. How might you test your hypothesis by extendi
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google

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