1.The balanced chemical equation is as below
Cu + 2 Ag(NO)₃ → Cu(NO₃)₂ +2 Ag
2.The much silver produced is 50.9 g
Step 1: find the moles of Cu
moles = mass÷ molar mass
from periodic table the molar mass of Cu = 63.5 g/mol
moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236 moles
Step 2: use the mole ratio to determine the moles of Ag
from equation above Cu:Ag is 1:2
therefore the moles of Ag =0.236 moles x 2/1 =0.472 moles
Step 3: find the mass of Ag
mass = moles x molar mass
from periodic table the molar mass of Ag =107.87 g/mol
mass = 0.472 moles x 107.87 g/mol = 50.9 g
3. The much silver collected worth is 1.797 oz
convert 50.9 g to oz
that is 1 gram = 0.0353 oz
50.9 grams =? oz
<em>by cross multiplication</em>
={(50.9 grams x 0.0353 oz) / 1 gram} =1.797 oz
