The answer is going to be 2*sqrt(5). You have to split it into perfect squares for it to be simplified... so in this case, I had sqrt(4*5) because sqrt(4) can be simplified... so your answer would be sqrt(4)*sqrt(5) or 2sqrt(5)

8 0

3 years ago

Find an equation perpendicular to x=1 and passing through (8,-9)

valina [46]

Answer:

$y=-9$

Step-by-step explanation:

We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).

Note that x=1 is a vertical line since x is 1 no matter what y is.

This means that if our new line is perpendicular to the old, then it must be a horizontal line.

So, since we have a horizontal line, then our equation must be our y-value of our point.

Our y-coordinate of our point (8,-9) is -9.

Therefore, our equation is:

$y=-9$

And this is in standard form.

And we're done!

3 0

3 years ago

If p and q are distinct primes. Find the number of positive divisors of p^2 * q^2

kkurt [141]

Answer:

Step-by-step explanation:

We know that for $p^mq^n$ where p and q are different prime numbers the number of positive divisors are (m+1) (n+!)

We have given $p^2q^2$

So here m=2 and n=2

So number of positive divisors $=(2+1)\times (2+1)$ =9

So the number of positive divisors of $p^2q^2$ is 9

3 0

3 years ago

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