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Nikitich [7]
3 years ago
7

Pls can someone help me with this pls I’ll give brainliest

Chemistry
2 answers:
NeX [460]3 years ago
7 0

Answer:

the answer is b

Explanation:

Yakvenalex [24]3 years ago
3 0

Answer:

Molecule

Explanation:

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There are over 100 elements, but only
elena-14-01-66 [18.8K]

Answer:

Symbol_Element

He_Helium

Li_Lithium

Be_Beryllium

B_Boron

C_Carbon

N_Nitrogen

O_Oxygen

F_Fluorine

Ne_Neon

Na_Sodium

Mg_Magnesium

Al_Aluminum

Si_Silicon

P_Phosphorous

S_Sulfur

Cl_Chlorine

Ar_Argon

K_Potassium

Ca_Calcium

Sc_Scandium

Ti_Titanium

V_Vanadium

Cr_Chromium

Mn_Manganese

Fe_Iron

Co_Cobalt

Ni_Nickel

Cu_Copper

Zn_Zinc

Ga_Gallium

Ge_Germanium

As_Arsenic

Se_Selenium

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6 0
3 years ago
Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of
igomit [66]

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.00154 mol/L
  • Initial volume (V₁): 230. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 660. mL

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

5 0
3 years ago
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
musickatia [10]

Answer:

T_2=335.42K=62.27^oC

Explanation:

Hello,

In this case, by using the general gas law, that allows us to understand the pressure-volume-temperature relationship as shown below:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, solving for the temperature at the end (considering absolute units of Kelvin), we obtain:

T_2=\frac{P_2V_2T_1}{P_1V_1}=\frac{1.8L*0.75atm*(25+273.15)K}{1.2L*1.0atm} \\\\T_2=335.42K=62.27^oC

Best regards.

4 0
3 years ago
Read 2 more answers
Products: 1-methylcyclohexene, 3-methylcyclohexene, methylenecyclohexane
Lostsunrise [7]

Answer:

See explanation

Explanation:

The reaction that we are considering here is quite a knotty reaction. It is difficult to decide if the mechanism is actually E1 or E2 since both are equally probable based on the mass of scientific evidence regarding this reaction. However, we can easily assume that the methylenecyclohexane was formed by an E1 mechanism.

Looking at the products, one could convincingly assert that the reaction leading to the formation of the two main products proceeds via an E1 mechanism with the formation of a carbocation intermediate as has been shown in mechanism attached to this answer. Possible rearrangement of the carbocation yields the 3-methylcyclohexene product.

8 0
3 years ago
Which statements are true about Figure I and Figure II below? (Check all that apply)
Scilla [17]

Both figures are mixtures,

Figure II is a heterogenous mixture

Figure I is a homogenous mixture

5 0
3 years ago
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