1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka [77]
3 years ago
7

How do the elephants help to maintain the population of birds that you can see perched on their backs?

Chemistry
1 answer:
Zolol [24]3 years ago
6 0

You need to answer this question because we don't do your

homework and it is asking for your opinion and to show your

critical thinking skills and how well you understood the the  lesson.

You might be interested in
Where is liquid waste held?
seraphim [82]
The answer is in the bladder.
8 0
3 years ago
Read 2 more answers
Ammonium phosphate is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid with ammonia . Wha
Dmitry [639]

Answer:

7.5 g

Explanation:

There is some info missing. I think this is the original question.

<em>Ammonium phosphate ((NH₄)₃PO₄) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H₃PO₄) with ammonia (NH₃). What mass of ammonium phosphate is produced by the reaction of 4.9 g of phosphoric acid? Be sure your answer has the correct number of significant digits.</em>

<em />

Step 1: Write the balanced equation

H₃PO₄ + 3 NH₃ ⇒ (NH₄)₃PO₄

Step 2: Calculate the moles corresponding to 4.9 g of phosphoric acid

The molar mass of phosphoric acid is 98.00 g/mol.

4.9 g \times \frac{1mol}{98.00g} = 0.050mol

Step 3: Calculate the moles of ammonium phosphate produced from 0.050 moles of phosphoric acid

The molar ratio of H₃PO₄ to (NH₄)₃PO₄ is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.050 mol = 0.050 mol.

Step 4: Calculate the mass corresponding to 0.050 moles of ammonium phosphate

The molar mass of ammonium phosphate is 149.09 g/mol.

0.050mol \times \frac{149.09 g}{mol} = 7.5 g

6 0
3 years ago
Explain how the following experimental errors affect the final calculation of the kilocalories per gram for a food item. Be spec
Ainat [17]

Answer:

a) the final kilocalories per gram for food will be less because the mass was reduced

b)the final kilocalories per gram for food will be less since

c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion

d) the final kilocalories per gram for food will be more.

Explanation:

a) the final kilocalories per gram for food will be less because the mass was reduced from 110.3 to 101.3g

b)the final kilocalories per gram for food will be less since some marshmallow fell off before the reaction

c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion

d) the final kilocalories per gram for food will be more since the thermometer that got stuck will add to the value of final kilocalories per gram

6 0
3 years ago
Does it require more force to stop a bus or a bike moving at the same speed
iVinArrow [24]
Well depends how fast they're going if it's a slow speed a bus but at a fast speed a bike because you wanna be careful while stopping
7 0
3 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
Other questions:
  • Which element in group 16 is most likely to gain an electron?
    11·1 answer
  • Please help me I'm so lost
    11·2 answers
  • HELP ASAP PLEASE!!!! 15 PTS!!
    12·2 answers
  • One atom of silicon can properly be combined in a compound with
    11·1 answer
  • How do valence electrons affect the properties of atoms?
    11·1 answer
  • The pressure inside of a tire is measured as
    10·1 answer
  • Ayudaaaaaaaaaaaaaaaaa​
    5·1 answer
  • What is the form of energy present in the pizza that we eat? group of answer choices mechanical chemical potential radiation.
    14·1 answer
  • PLEASE HELP ASAP I'M SO STRESSED
    9·1 answer
  • Would the plastic have a positive charge, negative charge, or no charge? *
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!