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kupik [55]
3 years ago
12

Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that

uses electrical energy
Chemistry
1 answer:
densk [106]3 years ago
4 0

Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that uses electrical energy.

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What type of solvent is needed to remove an oil stain?
Aliun [14]
The type of solvent that is needed to remove an oil stain would be an organic solvent. This is would dissolve the oil from the fabric to the solvent. Oil is nonpolar which would have the same polarity of an organic solvent. Hope this answers the question. Have a nice day.
5 0
3 years ago
When placed in a 200-mL square box, a substance has a spherical shape and has a volume of 75 mL. When placed in a 200-mL circula
Anastasy [175]

Answer:

a. Solid

Explanation:

<em>Solid substances do not change size or shape according to their containers</em>. In other words, solid substances keep their size and shape.

<em>Liquid and gas substances take the shape of their container</em>, so any of them would be square-shaped when put in a square box, and they would be spherical shaped when put in a spherical container.

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3 years ago
Can someone explain these to me?
Artemon [7]
Objects on earth are held by the gravity of the Moon.
6 0
4 years ago
Which is a characteristic of nuclear fission?
FinnZ [79.3K]
A nucleus spontaneously splits and absorbs energy.
4 0
2 years ago
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
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