2 years ago

If 4.80 mol Ca mixed with 2 mol N2, which is the limiting reactant? 3Ca (s) + N2 (g) Ca3N2 (s)

1 answer:

Andreyy892 years ago

4 0

Nitrogen in the limiting reactant x

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olga55 [171]

The correct answer is species

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3 years ago

NeTakaya

sorry i don't know the answer i'm really sorry

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3 years ago

Elenna [48]

Answer:

Fe2(SO4)3 + 3BaCl2 → 2FeCl3 + 3BaSO4

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3 years ago

Jlenok [28]

Answer: The density of gold in $g/cm^3$ is $19.22g/cm^3$

Explanation:

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

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4 years ago

BlackZzzverrR [31]

Na3P is the formula if that helps

6 0

3 years ago