If 4.80 mol Ca mixed with 2 mol N2, which is the limiting reactant? 3Ca (s) + N2 (g) Ca3N2 (s)
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Option (B) is the right answer.
Hydronium ion () concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.
The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) :
Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.
<h3>Given: </h3>pH1( initial pH) = 2.0
pH2( initial pH) = 4.0
[H3O+] = initial hydronium concentration
[H3O+]* = final hydronium concentration
<h3>Formula used : </h3><h3>Solution: </h3>
Thus , the concentration of hydronium ion decreases by 100.
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If we remove 2 electrons, the new charge will be positive by 2 units. Hence, the ion is 
.