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3 years ago

Which of the following compounds does NOT contain molecules? Question 2 options: CO2 H2 NaCl H2O

Chemistry

1 answer:

-Dominant- [34]3 years ago

3 0

NaCl, molecules are ionic bonding this is covalent

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Strong acids are corrosive in nature

Yuri [45]

Yes. Strong bases are too. In fact, they’re more dangerous to your skin than acids.

8 0

3 years ago

Determine the concentration of a solution of sodium hydroxide (NaOH) using a 0.500M Potassium Hydrogen Phthalate (KHP) standard

Svetradugi [14.3K]

Answer:

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

Explanation:

The KHP reacts with NaOH as follows:

KHP + NaOH → KNaP + H₂O

Where 1 mole of KHP reacts per mole of KNaP

That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.

Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:

Moles KHP = Moles NaOH:

25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH

Molarity NaOH:

0.01275 moles NaOH / 0.0300L =

<h3>0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL</h3>

7 0

3 years ago

The removal of one or more electrons from a neutral atom results in and

Studentka2010 [4]

Answer:

The removal of one or more electrons from a neutral atom results in a cation.

Explanation:

When you remove electrons from a neutral atom, the atom becomes more positive. Electrons have a negative charge and the protons inside of the nucleus have a positive charge. When electrons are removed, the positive charges from the protons outweigh the negative charges. This results in a positively charged atom, called a cation.

6 0

2 years ago

For each image, select the state of matter represented.

kifflom [539]

Answer:

need image

Explanation:

5 0

3 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

3 years ago