A HARD DRIVE COST 225,plus 40 hours per hour

Jordan takes 50% of the cherries from a bowl. Then Mei takes 50% of the remaining cherries. Finally Greg takes 50% of the remain

Lynna [10]

If 3 is 50%

3 x 2 = 6

If 6 is another 50%

6 x 2 = 12

If 12 is another 50%

12 x 2 =24

Therefore there were 24 cherries in the bowl!

8 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago

What is the Kinetic energy of a 2000 kg bus that is moving at 30m/s? Explain please

agasfer [191]

There's a formula for that.

KE = (1/2)mv²

... = (1/2)(2000 kg)(30 m/s)²

... = 900,000 kg·m²/s²

... = 900,000 J

_____

It is helpful to know the relationship between kilograms, meters, seconds, and Newtons or Joules.

1 J = 1 kg·m²/s²

4 0

4 years ago

The distance from your house to the park is represented by the expression "5x + 4 more than 2 − 2x." The distance from the park

Neko [114]

Answer:

The distance from the house to the school is equal to $(4x-2)$

Step-by-step explanation:

Let

A-----> the distance from house to the park

B----> the distance from the park to the school

C----> the distance from house to the school

so

$C=A+B$

we know that

$A=(2-2x)+(5x+4)$

$B=(3x-10)-(2x-2)$

so

Find the the value of C

$C=(2-2x)+(5x+4)+(3x-10)-(2x-2)$

$C=(4x-2)$

therefore

The distance from the house to the school is equal to $(4x-2)$

6 0

3 years ago

each digit in the division example has been replaced with the same letter throughout (r stand for remainder) the digits used wer

Vilka [71]

Theres not really enough information to work from here. Is there anymore to this problem???

5 0

4 years ago