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ad-work [718]
2 years ago
6

Make u the subject of formula in M=m(v-u).u​

Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer:

u = v - 1

Step-by-step explanation:

I'm guessing the formula you've given me is m = m(v - u), and I'm going to solve it that way. If it's actually different, let me know so I can redo the answer! :)

So, we have the equation m = m(v - u) and we're trying to make u the subject, or isolate it on one side of the equation. Right now, it's being subtracted from v and then multiplied by m. Let's start by dividing both sides of the equation by m so we can stop multiplying (v - u) by m.

m = m(v - u)

m/m = m(v-u)/m

1 = v - u

Now, our equation is pretty simple, but our u is still being subtracted from v, so we should add a u to both sides.

1 = v - u

1 + u = v - u + u

1 + u = v

Now, we're adding 1 to u, so let's go ahead and subtract 1 from both sides.

1 + u = v

1 - 1 + u = v - 1

u = v - 1

And we now we have u as the subject of our formula.

Hopefully that was helpful! :)

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

Diagonal 2(BD) = \sqrt{(2-2)^2+(3+5)^2} = 8 units

Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

                                                       = \frac{1}{2}\times 4\times 8

                                                       = 16 units²

Therefore, area of the given rhombus is 16 units².

5 0
3 years ago
If P(A) = 0.2, P(B) = 0.2, and P(A ∪ B) = 0.4, then P(A ∩ B) = _______.
Pavlova-9 [17]

Answer:

P(A ∩ B) = 0.

a) NO

b) YES

Step-by-step explanation:

Thinking about this through Venn diagrams we can sort of understand that:

if P(A) = 0.2 and P(B) = 0.2, and P(A∪B) = 0.4.

there's no overlapping between P(A) and P(B).

(If there was overlapping then P(A∪B) < 0.4, since you'd be excluding the overlapped part from getting counted twice.

Think of it in terms of calculating areas circles A and B, if the circles were disjoint, then the sum of the areas A and B would be 0.2+0.2. But if the circles were overlapping then the sum of the areas would be 0.2+0.2-P(A ∩ B), where P(A ∩ B) is the overlapping part)

since there's no overlapping P(A ∩ B) = 0.

a) NO

events A and B are only independent when P(A ∩ B) > 0 (or overlapping)

b) YES

events A and B are mutually exclusive when P(A ∩ B) = 0 (or disjoint)

8 0
3 years ago
How do you write 9,800,100 in exponents and expanded form
Leokris [45]
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Happy to Help!
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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8 \frac{1}{3}

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