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3 years ago

7

Everyone out there stop moaning around!! Move on with your lives!! Stop posting nonsense boo-hoo c.ra.p on this!! Talk to a ther

apist!! We get tired of hearing your cr.a.p!! Move on in your life!! Make a Da.mn MOVE!!

2 answers:

Daniel [21]3 years ago

8 0

Answer: This should be under the subject English or Art, not math.

Step-by-step explanation: Go motivation, if a little rude.

Zina [86]3 years ago

8 0

Answer:

Love the message maybe say it in a more positive way if they are complaining they don't need negative criticism

Step-by-step explanation:

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Solve the inequality.<br><br> 2(4x – 3) ≥ –3(3x) + 5x?

Alinara [238K]

Answer:

x≥1/2

Step-by-step explanation:

6 0

3 years ago

THANKS FOR ANSWERING ✔✔

Yuki888 [10]

4.68, 3/12, -4, -4 12/25

7 0

3 years ago

Read 2 more answers

Three forces act on an object. Two of the forces are at an angle of 95◦ to each other and have magnitudes 35 N and 7 N. The thir

Cerrena [4.2K]

We want to find $\vec F_4$ such that the object needs is in equilibrium:

$\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0$

We're told that $F_1=35\,\mathrm N$ , $F_2=7\,\mathrm N$ , and $F_3=9\,\mathrm N$ . We also know the angle between $\vec F_1$ and $\vec F_2$ is 95º, which means

$\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ$

$\vec F_3$ is perpendicular to both $\vec F_1$ and $\vec F_2$ , so $\vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0$ .

If we take the dot product of $\vec F_1$ with the sum of all four vectors, we get

$\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0$

${F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0$

$\implies\vec F_1\cdot\vec F_4=-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)$

We can do the same thing with $\vec F_2$ and $\vec F_3$ :

$\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)$

$\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies\vec F_3\cdot\vec F_4=-{F_3}^2$

Finally, if we do this with $\vec F_4$ , we get

$\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0$

$\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)$

$\implies{F_4}^2=-\left(-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)-{F_3}^2\right)$

$\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}$

$\implies\boxed{F_4\approx36.2\,\mathrm N}$

7 0

3 years ago

Find the distance between the points (-10, 9) and (2, -7).<br> Hint: Use the Pythagorean theorem

Aleksandr [31]

The distance between -10 and 9 is 19 and the distance between 2 and -7 is 9

Hope this helps

7 0

2 years ago

Need help with this the question is in the photo

Alik [6]

I would live to help but i cannot see the wuestion very well.. mind writting it oit in a commet?

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3 years ago