Answer:
9000 ft
Step-by-step explanation:
Given: A airplane is ascending at a constant rate of 15 feet per second,
What we need to know: The change in altitude during 10 minutes of flight,
60 seconds = 1 minute
60 × 10
= 600 seconds
600 × 15
= 9000 ft
Therefore there was a 9000 ft change in altitude during the 10 minutes of the flight.
Answer:
243 cm^2 + 108 cm^2 = 351 cm^2
Step-by-step explanation:
So, we have a rectangle and two triangles, we know all the sides or angles.
Rectangle: with 9 cm lenght 15cm + 12 cm = 27 cm
Formula: A=wl -> A=9*27 = 243 cm^2
Trianlge: A=ab/2
Angle 90°
Side A 12 cm
Side B 18 cm - 9 cm = 9 cm
A=ab/2=12·9/2=54 cm times 2 (for the opposite side) = 108 cm^2 = 351 cm^2
Answer: .235
Step-by-step explanation:
Total Distance - Shim 1 - Shim 2 - Shim 3 = Shim4
1.2 cm - 0.75 cm - 0.125 - 0.09 cm = 0.235 cm
Answer:
![\large\boxed{S.A.=96\ cm^2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BS.A.%3D96%5C%20cm%5E2%7D)
Step-by-step explanation:
We have:
(1) two trapezoids with bases b₁ = 7cm and b₂ = 5cm and the height h = 4cm
(2) three rectangles 3 cm × 7 cm, 3 cm × 4 cm and 3 cm × 5 cm.
The formula of an area of a trapezoid:
![A=\dfrac{b_1+b_2}{2}\cdot h](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bb_1%2Bb_2%7D%7B2%7D%5Ccdot%20h)
Substitute:
![A=\dfrac{7+5}{2}\cdot4=24\ cm^2](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B7%2B5%7D%7B2%7D%5Ccdot4%3D24%5C%20cm%5E2)
Calculate the areas of the rectangles:
![A_1=(3)(7)=21\ cm^2\\\\A_2=(3)(4)=12\ cm^2\\\\A_3=(3)(5)=15\ cm^2](https://tex.z-dn.net/?f=A_1%3D%283%29%287%29%3D21%5C%20cm%5E2%5C%5C%5C%5CA_2%3D%283%29%284%29%3D12%5C%20cm%5E2%5C%5C%5C%5CA_3%3D%283%29%285%29%3D15%5C%20cm%5E2)
The Surface Area:
![S.A.=(2)(24)+21+12+15=96\ cm^2](https://tex.z-dn.net/?f=S.A.%3D%282%29%2824%29%2B21%2B12%2B15%3D96%5C%20cm%5E2)