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sesenic [268]
3 years ago
7

A ramp has a horizontal distance of 10 feet and a vertical rise of 3 feet. Find the length of the ramp. Round to the nearest ten

th.
Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Tye length of the ramp can be gotten using Pythagoras theorem.

Horizontal distance = 10ft.

Vertical distance = 3ft

Length of the ramp² = 10²+3²

Length of the ramp² = 100+9

Length of the ramp² = 109

L² = 109

L =√109

L = 10.44ft

Hence the length of the ramp is 10.4ft to the nearest tenth

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The ratio of the measure of the sides of the triangle is 1/6: 1/3: 1/4 if the perimeter of the triangle is 13.5 inches find the
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Answer:

The shortest side of the triangle is 3 inches.

Step-by-step explanation:

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The ratio of the measure of the sides of the triangle is 1/6: 1/3: 1/4.

The perimeter = 13.5 inches.

Now, to find the shortest side.

<em>Let the one side be \frac{1}{6}x</em>

<em>And the second side be  \frac{1}{3}x.</em>

<em>And the third side be  \frac{1}{4}x.</em>

According to question:

\frac{1}{6}x+\frac{1}{3}x+\frac{1}{4}x=13.5

⇒\frac{x}{6}+\frac{x}{3}+\frac{x}{4}=13.5

Adding all the variables by taking common denominator we get:

⇒\frac{9x}{12}=13.5

<em>Multiplying both sides by 12 we get</em>:

⇒9x=162

<em>Dividing both sides by 9 we get</em>:

⇒x=18

Thus, <em>the sides of the triangle are</em>:

<u>1/6×18=3 inches.</u>

<u>1/3×18=6 inches.</u>

<u>1/4×18=9/2=4.5 inches</u>.

Therefore, the shortest side of the triangle is 3 inches.

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