The equation of the perpendicular line to the given line is: y = -5/4x - 30.
<h3>What is the Equation of Perpendicular Lines?</h3>
The slope values of two perpendicular lines are negative reciprocal of each other.
Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.
Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.
Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:
20 = -5/4(-40) + b
20 = 50 + b
20 - 50 = b
b = -30
Substitute m = -5/4 and b = -30 into y = mx + b:
y = -5/4x - 30
The equation of the perpendicular line is: y = -5/4x - 30.
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If AB = BC then set up the equation 3x - 4 = 5x - 10
Subtract 3x.
-4 = 2x - 10
Add 10.
6 = 2x
Divide by 2.
3 = x
AB is 3x - 4 so
3(3) - 4
9 - 4
5.
AB = 5
If AB is not equal to BC then this is not solvable.
But if they are I am sure AB = 5.
Hope this helps
57.6² = 33.8² + QR²
QR² = 2.175,32
QR = 46.64
57.6/sen90º = 46.64/sen(P)
sen(P) = 46.64*sen90º/57.6
sen(P) = 0.809
angle P is sen^-1 = 54.06º ≈ 54.1º
The greatest common factor of 20 and 30 is 10. This is because 10 is the largest number that when it is used to divide 20 or 30, it equals a whole number.
The simple way for us to solve is to write down the factors of both numbers, find the factors that match for both numbers, and see which is the largest out of those that match.
20: <u>1</u>,<u>2</u>,4,<u>5</u>,<u>10</u>,20
30: <u>1</u>,<u>2</u>,3,<u>5</u>,6,<u>10</u>,15,30
Using that logic, we can see that 10 is the greatest factor that the numbers share.
