Calculate the molarity of a solution prepared by dissolving 11.5 g naoh in enough water to make 1.5 l of solution. 1. 7.6 m 2. 2
.3 m 3. 0.19 m 4. 0.43 m
2 answers:
Molarity of a solution = (number mol of solute)/ (volume of the solution)
1) Molar mass NaOH= M(Na)+M(O)+M(h)= 23.0+16.0+1.0=40.0 g/mol
2) 11.5 g NaOH *(1mol Naoh/40.0 g NaOH)=0.288 mol NaOH
3)Molarity (NaOH solution) =(0.288 mol)/(1.5 L)=0.192 M≈0.19 M
<u>Answer:</u> The molarity of the solution is 0.19 M
<u>Explanation:</u>
To calculate the molarity of the solution, we use the equation given as:
![\text{Molarity}=\frac{\text{Mass of solute(in grams)}}{\text{Molar mass of solute(in g/mol)}\times \text{Volume of solution (in L)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%28in%20grams%29%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20solute%28in%20g%2Fmol%29%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%20%28in%20L%29%7D%7D)
We are given:
Mass of NaOH = 11.5 g
Molar mass of NaOH = ![[23+16+1]g/mol=40g/mol](https://tex.z-dn.net/?f=%5B23%2B16%2B1%5Dg%2Fmol%3D40g%2Fmol)
Volume of the solution = 1.5 Liters
Putting values in above equation, we get:
![\text{Molarity of solution}=\frac{11.5g}{40g/mol\times 1.5L}=0.19mol/L=0.19M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20solution%7D%3D%5Cfrac%7B11.5g%7D%7B40g%2Fmol%5Ctimes%201.5L%7D%3D0.19mol%2FL%3D0.19M)
Hence, the molarity of the solution is 0.19 M
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