El amoniaco y el fluor reaccionan para formar tetrafluoruro de dinitrogeno y fluoruro de hidrogeno. segun la reaccion: NH3 + F2
⇒ N2F4 + HF si reaccionan 5 gramos de amoniaco y 20 gramos de Fuor, ¿Cuantos gramos de fluoruro de hidrogeno se producen?
1 answer:
Answer:
son 12.6 gramos de HF
Explanation:
Tienes que saber qual es el reactor limitante en este caso es fluoruro con los 20 gramos puedes producer .631 mol qual son 12.6 gramos
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