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Juli2301 [7.4K]
3 years ago
12

El amoniaco y el fluor reaccionan para formar tetrafluoruro de dinitrogeno y fluoruro de hidrogeno. segun la reaccion: NH3 + F2

⇒ N2F4 + HF si reaccionan 5 gramos de amoniaco y 20 gramos de Fuor, ¿Cuantos gramos de fluoruro de hidrogeno se producen?
Chemistry
1 answer:
White raven [17]3 years ago
5 0

Answer:

son 12.6 gramos de HF

Explanation:

Tienes que saber qual es el reactor limitante en este caso es fluoruro con los 20 gramos puedes producer .631 mol qual son 12.6 gramos

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The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.

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The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.

Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.

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